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Auxiliary LEDs - Lightbars, Lights, Pods

Lollo050968

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Here's a very inelegant way of mounting a 10" lightbar to the bumper.
View attachment 7839113
View attachment 7839114
Zero drilling.
Ineos, please add DTP 2-pin connectors to the electrical wiring under the bonnet or at least make them longer. They were a pain to lengthen.
Nice, but I am a little bit afraid of everything in front of the cooler. I remember one comment of an Ineos engineer, who said that the engines could have a temperature problem, and for that reason it was not possible to mount the extra coolers higher, or make the engine cooler smaller. Everything in the front make the cooling surface smaller
 

grnamin

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Nice, but I am a little bit afraid of everything in front of the cooler. I remember one comment of an Ineos engineer, who said that the engines could have a temperature problem, and for that reason it was not possible to mount the extra coolers higher, or make the engine cooler smaller. Everything in the front make the cooling surface smaller
Hence, my no-drilling method of mounting the lightbar. If I experience any overheating issues, I'll remove it or relocate.
 

crimson

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Please excuse my poor knowledge on this topic and the question to follow :).

For the EXT 3 switch (25a), would it be SAFE and possible to run the below 2 x light bars at the same time on high?


1704861160102.png


I see in the spec that it states that a Current Draw on 24v on High is 9.73A, while on Low it is 1.78A. So if the EXT3 voltage is 24v, this should be possible, however if it's 12v, then the Current Draw is 19.50A on High which will push it well over.

Thanks
 

anand

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Please excuse my poor knowledge on this topic and the question to follow :).

For the EXT 3 switch (25a), would it be SAFE and possible to run the below 2 x light bars at the same time on high?


View attachment 7839202

I see in the spec that it states that a Current Draw on 24v on High is 9.73A, while on Low it is 1.78A. So if the EXT3 voltage is 24v, this should be possible, however if it's 12v, then the Current Draw is 19.50A on High which will push it well over.

Thanks
There is no 24v system, everything on the Grenadier is 12v; so no, the EXT3 switch could not handle 2 of those light bars
 

AnD3rew

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Please excuse my poor knowledge on this topic and the question to follow :).

For the EXT 3 switch (25a), would it be SAFE and possible to run the below 2 x light bars at the same time on high?


View attachment 7839202

I see in the spec that it states that a Current Draw on 24v on High is 9.73A, while on Low it is 1.78A. So if the EXT3 voltage is 24v, this should be possible, however if it's 12v, then the Current Draw is 19.50A on High which will push it well over.

Thanks
No, you won’t be able to run 2, definitely no go.
 
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When you are fitting additional lights it is always best (IMO) to fit a control relay,
The switchable power is used to energise the relay (Pin 86 is the norm)
Pin 85 goes to ground (earth)
A live feed on a suitably sized cable, via fuse is fed to Pin 30 and the cable to power the lamps is fed from Pin 87.

eBay has relays like this for around the £5 mark, some include a fitted fuse (which I reccommend).
Pretty much all of these relays can cope with 40A so i'd reccomment that each lamp has it's own relay.
Use a good quality multicored 6AWG cable from the 12V source to Pin 30 and from Pin 87 to the lamp and fit a (max) 30A fuse.

The relay will typically draw less than 1/2 an Amp so there is really no strain on the switch or the cables.
If a lamp stops working, its easy to trace the cirucuit and discover what is wrong.

If you get it wrong then you don't destroy the vehicles wiring/damage the looms in any way.
 
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This is the Ineos fitted light bar to my Rhino bars. Sorry I don't have a link to the parts but as you can see it's a right angled bracket attached to the bar slot via a T-slot stud. (edit, sorry was talking and typing at the same time, on closer inspection not a stud but perhaps a bolt thru on to T-bracket, but the result is the same).
Thanks.
Where did the bracket come from?
 

AWo

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My choice would be

The Swedish Strands Siberia Outlaw 32". More than 21500 Lux on the first 10 meters, 1 Lux @ 1466 m.

As a comparison, a normal LED headlight is around 150 to 450 Lux @ 10 m, depending on the type.

However, you need an (almost) free area, like Swedish E-Roads, where the trees are at least 20 meters away from the road or even more open roads. If you drive through dense forest, you will only dazzle yourself.

AWo
 

Jiman01

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However, you need an (almost) free area, like Swedish E-Roads, where the trees are at least 20 meters away from the road or even more open roads. If you drive through dense forest, you will only dazzle yourself.

AWo
Or start a forest fire 😂
 

marcusnilsson

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My choice would be

The Swedish Strands Siberia Outlaw 32". More than 21500 Lux on the first 10 meters, 1 Lux @ 1466 m.

As a comparison, a normal LED headlight is around 150 to 450 Lux @ 10 m, depending on the type.

However, you need an (almost) free area, like Swedish E-Roads, where the trees are at least 20 meters away from the road or even more open roads. If you drive through dense forest, you will only dazzle yourself.

AWo

How will you wire that to avoid blowing a fuse?

  • Voltage (V DC): 10-30V DC
  • Theoretical effect (w) 12V: 600
  • Theoretical effect (w) 24V: 600
  • Consumption (w) 12V: 409,2
  • Consumption (w) 24V: 398,1
 

AWo

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With wires thick enough, 2.5 qmm at a minimum or 24 V. The wire of the light bar is thick, very thick, I assume 2,5 qmm.

I'll check that and post a picture of the cable this evening.

AWo
 

Andrew Kilby

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As I said, there will be differences in the final forces based on the differential weights/mass of the vehicles and the way in which they deform etc. so yes not exactly the same as a wall. But the point is that you can’t add the speeds of the two vehicles together. A head on between two vehicles doing 100kph is not equivalent to one vehicle doing 200kph.
You are 100% incorrect. Newton 3rd law of motion states. For every action there is an equal and opposite reaction. Two vehicles travelling at100 km in a head on will stop where they hit. A vehicle travelling at 100 km hitting stationary car will move the stationary car in the direction of travel. A vehicle travelling at 200 km hitting the stationary car will move it twice as far. Ignoring variable friction quotients.
 

Krabby

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You are 100% incorrect. Newton 3rd law of motion states. For every action there is an equal and opposite reaction. Two vehicles travelling at100 km in a head on will stop where they hit. A vehicle travelling at 100 km hitting stationary car will move the stationary car in the direction of travel. A vehicle travelling at 200 km hitting the stationary car will move it twice as far. Ignoring variable friction quotients.
While the force placed upon each vehicle would be equal, the respective resulting accelerations would not be equal. MASS COMES INTO PLAY! (Newton's Second Law) Where p=mv (momentum = mass x velocity).

If a Grenadier is traveling at 100 kph (27.78 meters per sec) it's momentum has a value of 75,006 kg-mps (2700 kg x 27.78 mps), whereas a Mazda Miata/MX5 also traveling 100 kph has a momentum of 30,308 kg-mps (1091 kg x 27.78 mps) (again, it's way more complicated than this, put for all intents and purposes the force is equivalent but where things end up is not). I believe in order for these two vehicles to "rebound" the same distance (which I think would essentially be a dead stop), the Miata has to be traveling around 250 kph!

Edit -I'm not a physicist but play one on TV

Second edit - from HERE
"...Newton's third law of motion is naturally applied to collisions between two objects. In a collision between two objects, both objects experience forces that are equal in magnitude and opposite in direction. Such forces often cause one object to speed up (gain momentum) and the other object to slow down (lose momentum). According to Newton's third law, the forces on the two objects are equal in magnitude. While the forces are equal in magnitude and opposite in direction, the accelerations of the objects are not necessarily equal in magnitude. In accord with Newton's second law of motion, the acceleration of an object is dependent upon both force and mass. Thus, if the colliding objects have unequal mass, they will have unequal accelerations as a result of the contact force that results during the collision.

u4l2a2.gif
Consider the collision between the club head and the golf ball in the sport of golf. When the club head of a moving golf club collides with a golf ball at rest upon a tee, the force experienced by the club head is equal to the force experienced by the golf ball. Most observers of this collision have difficulty with this concept because they perceive the high speed given to the ball as the result of the collision. They are not observing unequal forces upon the ball and club head, but rather unequal accelerations. Both club head and ball experience equal forces, yet the ball experiences a greater acceleration due to its smaller mass. In a collision, there is a force on both objects that causes an acceleration of both objects. The forces are equal in magnitude and opposite in direction, yet the least massive object receives the greatest acceleration."

Third edit - please tell me where have a physicist (or physics teacher) here who can explain this for real. I think what I am saying is correct, but Physics 201 was 30 years ago!
 
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anand

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@Krabby your high school educator is showing :ROFLMAO:
 
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